find the value of k if 2 is the one of the root of the quadratic equation X²- kx+6=0
Answers
Answered by
7
k=5 see the pic for the ans
Attachments:
Answered by
7
Given that one root is 2 ,
x = 2
=============================
putting the value of x in given equation,
x² - kx + 6 = 0
(2)² - k(2) + 6 =0
4 - 2k = -6
-2k = - 6 - 4
-2k = -10
2k =10
k = 10/2
k = 5
x = 2
=============================
putting the value of x in given equation,
x² - kx + 6 = 0
(2)² - k(2) + 6 =0
4 - 2k = -6
-2k = - 6 - 4
-2k = -10
2k =10
k = 10/2
k = 5
abhi569:
3(-1/3)^2 - 5(-1/3) - 2 = 0
3(1/9) + 5/3 - 2 = 0
1/3 + 5/3 - 2 =0
taking LCM, (1 + 5 - 6)/3 = 0
(6 - 6)/3 = 0
0/3 = 0
0 = 0
hence, 2 and -1/3 are roots.....hope it help s
(-:
Similar questions