find the value of k if 2 is zero of 3x2 - 17x + k
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Answered by
1
Answer:
since 2 is the zero of the polynomial
therefore, 3(2)^2 - 17(2) + k = 0
12 - 34 + k = 0
k = 22
Answered by
4
k=22
Step-by-step explanation:
f(x)=3x^2 - 17x + k
x=2
therefore f(2)=3(2)^2-17(2)+k=0
=3(4)-34+k=0
=12-34+k=0
=-22+k=0
k=22
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