Math, asked by danishzehenx2x, 8 months ago

Find the value of k if (-2)k+1 × (-2)3

= (-2)7​

Answers

Answered by Anonymous
417

Answer:

k = 4

Step-by-step explanation:

(-2)k+1 × (-2)3  = (-2)7​

-2k + -6 = -14

- 2k = -14 + 6

- 2k = - 8

k = -8 / -2

k = 4

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Answered by pulakmath007
51

The required value of k = 3

Given :

\displaystyle \sf{  {( - 2)}^{k + 1}  \times  {( - 2)}^{ 3}  =  {( - 2)}^{7}  }

To find :

The value of k

Formula :

We are aware of the formula on indices that :

 \sf{  {a}^{m}  \times  {a}^{n} =  {a}^{m + n}  }

Solution :

Step 1 of 2 :

Write down the given equation

The given equation is

\displaystyle \sf{  {( - 2)}^{k + 1}  \times  {( - 2)}^{ 3}  =  {( - 2)}^{7}  }

Step 2 of 2 :

Find the value of k

\displaystyle \sf{  {( - 2)}^{k + 1}  \times  {( - 2)}^{ 3}  =  {( - 2)}^{7}  }

\displaystyle \sf{ \implies  {( - 2)}^{k + 1 + 3}   =  {( - 2)}^{7}  }

\displaystyle \sf{ \implies  {( - 2)}^{k + 4}   =  {( - 2)}^{7}  }

Comparing both sides we get

\displaystyle \sf{   k + 4 = 7}

\displaystyle \sf{ \implies  k  = 7 - 4}

\displaystyle \sf{ \implies  k  = 3}

Hence the required value of k = 3

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