Math, asked by chneetu490, 19 days ago

Find the value of k if (-2)k+1× (-2)3= (-2)7

Answers

Answered by Trashvapes
0

Answer:

4

Step-by-step explanation:

-2)k+1 × (-2)3  = (-2)7​

-2k + -6 = -14

- 2k = -14 + 6

- 2k = - 8

k = -8 / -2

k = 4

Answered by divyapakhare468
0

To find : value of k

Given equation : (-2) ^{k +1}  \times (-2)^{3} = (-2)^{7}  

Solution :

  • As we have to find the value of  k, we transpose constant term to RHS leaving variable term at LHS .  
  • Given data: (-2) ^{k +1}  \times (-2)^{3} = (-2)^{7}  

                                      (-2)^{K + 1} = \frac{(-2)^{7} }{(-2)^{3} }  

  • According to law of indices If the bases of two numbers in the division are the same, then exponents are subtracted and the base will be the same.

          \frac{x^{a}}{x^{b}}=x^{a-b}$.

  • We will apply the above exponents rules, as bases are same ,we get

             $$\begin{array}{l}=2^{7-3} \\=2^{4} \\\end{array}$$  

  • We will apply the above exponents rules, as bases are same ,we get
  • Now, equating exponents of LHS and RHS

                         k + 1 = 4 \\k = 4-1\\k = 3

Hence , value of k will be 3.

                 

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