Question

Find the value of k if (−2) ^ k+1 ÷ (−2) ^ 4 = (−2)^ 6

Answer 1

Step-by-step explanation:

(−k+1)(2−2k−6+2k)+k(6−2k−2k)+(−4−k)(2k−2+2k)=0

(−k+1)(−4)+k(6−4k)+(−4−k)(4k−2)=0

4k−4+6k−4k

2

−16k+8−4k

2

+2k=0

−2k

2

−k+1=0

2k

2

+k−1=0

2k

2

+2k−k−1=0

2k(k+1)−1(k+1)=0

(k+1)(2k−1)=0

k=−1 or k=

2

1