Question

Find the value of k , if (-2)^k+1 x (-2)^3 =(-2)^7

Answer 1

Hi!

The answer for your question is k = 3

Step-by-step explanation:

$(-2)^{k+1}$ × $(-2)^{3}$ = $(-2)^{7}$

By the laws of exponents, $a^{m}$ × $a^{n}$ = $a^{m+n}$

So, applying it here,

$(-2)^{k+1+3}$ = $(-2)^{7}$

$(-2)^{k+4}$ = $(-2)^{7}$

Since the bases are equal, we can equate their powers. So,

k + 4 = 7

k = 7 - 4 = 3

I hope it helps

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