find the value of k if 2 x minus 3 is a factor of 2 x cube minus 9 X square + X + k
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Let g(x) be 2x-3
Then 2x-3=0
2x=3
x=3/2
Let 2x^3-9x^2+x+k=p(x)
Put the value of x.
2*3/2*3/2*3/2-9*3/2*3/2+3/2+k=0
27/4-81/4+3/2+k=0
27-81+6+k=0
-48+k=0
k=48
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