Question

find the value of k, if (2k+1), 13 and 5k-3 are three consecutive terms of an AP

Answer 1

Hey MATE!

If the above are 3 consecutive term of an AP then we can apply 2b = a + c

2(13) = (2k+1) + (5k-3)

26 = 7k - 2

28 = 7k

k = 4. Answer

Hope it helps

Hakuna Matata :))

Answer 2

● Arithmetic progression ●

(2k + 1), 13 and (5k - 3) are the consecutive terms of an AP.

To find : - k = ?

The common difference between the three terms must be same.

So,

13 - (2k + 1) = (5k - 3) - 13

=> 13 - 2k - 1 = 5k - 3 - 13

=> - 2k - 5k = - 16 - 12

=> - 7 k = - 28

=> k = - 28/ - 7

=> k = 4