Question

find the value of k if 2k+1 completly divides 8kx²-5x+2k

Answer 1

it completely divides it... means 2k+1 is one of the roots.


put x =2k+1 ..and put equation =0

$8k {x}^{2} - 5x + 2k = 0 \\ 8k(2k + 1) {}^{2} - 5(2k + 1) + 2k = 0$