Find the value of k if 2kx (x-6)+3 here two equal roots? (hint b^2-4ac=0)
Answers
Answered by
12
SOLUTION:-
Answer
• k= 1/6
Given
• 2kx(x-6) +3
To find
• Value of k
Explanation
☆ __ 2kx(x-6)+3__ ☆
➡️ 2kx²-12kx +3 =0
a= 2k
b= -12k
c= 3
Now, We know that
➡️ b²-4ac=0 ⬅️
Putting values
➡️ (-12k)² - 4×2k × 3 =0
➡️ 144k² - 24k = 0
➡️ k(144k - 24)=0
➡️ 144k -24 =0
➡️ 144k = 24
➡️ k= 24/144
➡️k= 1/6
So , The value of k is 1/6
________________________________
Answered by
0
SOLUTION:-
Answer
• k= 1/6
Given
• 2kx(x-6) +3
To find
• Value of k
Explanation
2kx(x-6)+3
➡️ 2kx²-12kx +3 =0
a= 2k
b= -12k
c= 3
Now, We know that
➡️ b²-4ac=0 ⬅️
Putting values
➡️ (-12k)² - 4×2k × 3 =0
➡️ 144k² - 24k = 0
➡️ k(144k - 24)=0
➡️ 144k -24 =0
➡️ 144k = 24
➡️ k= 24/144
➡️k= 1/6
So , The value of k is 1/6
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