Find the value of k if 2x+1 is a factor of (3k+2x)²+(k-1)
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Step-by-step explanation:
Answer
Let take f(x)=(3k+2)x
3
+(k–1)
Now, 2x+1=0
x=−1/2
As, 2x+1 is a factor of f(x) then the remainder should be 0
f(−1/2)=(3k+2)(−1/2)
3
+(k–1)=0
∴(3k+2)(
2
−1
)
3
+(k−1)=0
⇒
8
−(3k+2)
+(k−1)=0
⇒
8
−3k−2+8k−8
=0
⇒5k−10=0
k=2
5k=10=0
k=2
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