Question

find the value of k, if 2x-1 is a factor of the polynomial 6x2+kx-2

Answer 1

Hello friends!!

Here is your answer :

P(x) = 6x² + kx - 2

g(x) = 2x - 1

Put g(x) = 0

2x - 1 = 0

x = 1/2

Therefore, g(x) is a factor of p(x).

Then, p( 1/2) = 0

$6 {( \frac{1}{2} )}^{2} + k( \frac{1}{2} ) - 2 = 0$


$6 \times \frac{1}{4} - 2+ \frac{1}{2} k = 0$


$\frac{3}{2} - 2 + \frac{1}{2} k = 0$


$\frac{3 - 4}{2} + \frac{1}{2} k = 0$


$\frac{ - 1}{2} + \frac{1}{2} k = 0$


$\frac{1}{2} k = \frac{1}{2}$


$k = \frac{1}{2} \times 2$


$k = 1$


Hope it helps you... ^_^

#Be Brainly

Answer 2

put value of x as 1/2 by putting 2x-1=0
then put x as 1/2 in polynomial then make it equal to zero and you will get value of K
6×1/2×2+k×1/2-2=0
solve this and find value of k