Question

Find the value of k if 2x-1 is a factor of the polynomial 6x ^ 2 + kx - 2​

Answer 1

Answer:

Let f(x) = 6x²+kx-2

Since factor of f(x) is 2x-1

Therefore, x= 1/2

Now, f(1/2)=

6×(1/2)² + k×(1/2) - 2=0

3/2 + k/2 - 2=0

(3+k-4)/2 =0

3 + k - 4 =0×2

-1 + k = 0

Therfore, k=1

Answer Given.

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