Find the value of K, if (2x - 1) is factor of f(x) = 2x3
- kx2 + 2
Answers
Answered by
2
Answer:
(2x−3) is a factor of p(x)=2x
3
−9x
2
+x+K,
If (2x−3)=0,x=
2
3
If (2x−3) is a factor of p(x) then p(
2
3
)=0
p(x)=2x
3
−9x
2
+x+K,
⇒p(
2
3
)=2(
2
3
)−9(
2
3
)+
2
3
+K=0
⇒2(
8
27
)−9(
4
9
)+
2
3
+K=0
⇒(
4
27
−
4
81
+
2
3
+K=0)×4
27−81+6+4K=0
−48+4K=0
4K=48
So K=12
Answered by
6
Answer:
k=9
Step-by-step explanation:
2x-1 is a factor of 2x³-kx²+2
that means when you substitute x=1/2 the value of f(x)=0
⇒2(1/2)³-k(1/2)²+2=0
⇒1/4-k/4+2=0
⇒1-k+8=0×4
⇒k=9
so value of k =9
hope you understand
mark as brainliest answer and follow me
Similar questions