Question

find the value of k, if 2x-1is a factor of polynomial 6x^2+kx-2

Answer 1

$2x - 1 = 1 \\ 2x = 2 \\ x = \frac{2}{2} \\ x = 1 \\ p(x) = 6x { }^{2} + kx - 2 \\ p(1) = 6 + k - 2 \\ p(1) = 4 + k \\ 0 = 4 + k \\ k = - 4$

Answer 2

Hii..

p(x)= 6x^2+kx-2

g(x)= 2x-1

=> 2x-1= 0

=> 2x=1

=> x=1/2

Putting x=1/2 in the above polynomial we get,

p(1/2)=0

6*(1/2)^2+k*(1/2)-2=0

=> 6*1/4+k/2-2=0

=> 3/2+k/2-2=0

=> 3+k/2-2=0

=> 3+k=2*2

=> 3+k= 4

=> k= 4-3

=> k= 1

Hope it helps!!