find the value of K if 2x-4 in p(x) = kx^2-3x+k
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Answered by
1
Answer:
solution 1:-
According to the Question
p(x) = kx² - 3x + k
If (x - 1) is a factor of p(x)
Therefore
x - 1 = 0
x = 1
Substitute the value of x in Equation
⇒ k(1)² - 3 × 1 + k = 0
⇒ 2k - 3 = 0
⇒ 2k = 3
⇒ k =
solution 2:-
Answer:
k = 3/2
Explanation:
p(x) = kx²-3x+k
If (x-1) is a factor of p(x) then
p(1) = 0
=> k(1)²-3×1 + k = 0
=> 2k - 3 = 0
=> 2k = 3
=> k = 3/2
Therefore,
Value of k = 3/2
••••
Answered by
0
Answer:
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