Find the value of K if ( 2x4 +3x3 +2kx2 +3x +6.) is exactly divisible by (x+2)
Akankshasrivastava:
give me this answer
Lol
If I knew I wouldn't have asked. XD
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heyy mate!!! here's ur ans
g(x) = x+2 =0
x=-2
p(-2) = 2*(-2)4+3*(-2)3+2k(-2)2+3*-2+6
=2*16+3*(-8)+2k*4+(-6)+6
=32-24+8k-6+6
=8+8k
8+8k = 0
8k = -8
k = -8/8
=-1
hope it will help
g(x) = x+2 =0
x=-2
p(-2) = 2*(-2)4+3*(-2)3+2k(-2)2+3*-2+6
=2*16+3*(-8)+2k*4+(-6)+6
=32-24+8k-6+6
=8+8k
8+8k = 0
8k = -8
k = -8/8
=-1
hope it will help
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