Question

Find the value of k if (3,4) lies on the graph of the equation 3y= kx-7

Answer 1

$answer$

3x4 = kx3 + 7

12 = 3 k+ 7

12 - 7 = 3k

5 = 3k

5/3 = k or 1.6

On putting x = 0 then y is 3y = 1.6 × 0 + 7

3y = 0 + 7

y = 7/3

y = 2.3

On putting x = 1 then y is 3y = 1.6 x1 +7

Зу = 1.6 + 7

3y =8.6

y = 8.6/3

Answer 2

Answer:

1 Answer. Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Hence, the value of a is 5/3.