Find the value of k if (3,4) lies on the graph of the equation 3y= kx-7
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3x4 = kx3 + 7
12 = 3 k+ 7
12 - 7 = 3k
5 = 3k
5/3 = k or 1.6
On putting x = 0 then y is 3y = 1.6 × 0 + 7
3y = 0 + 7
y = 7/3
y = 2.3
On putting x = 1 then y is 3y = 1.6 x1 +7
Зу = 1.6 + 7
3y =8.6
y = 8.6/3
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Answer:
1 Answer. Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point. Hence, the value of a is 5/3.
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