Question

Find the value of k if (-3,5)is a solution of 6x+3k=3y and write two solutions of it.

Answer 1

Hii!!
x=-3, y=5
6x+3k=3y
6(-3)+3k=3(5)
-18+3k=15
3k=15+18
3k=33
k=33/3
k=11

Two solutions of it are :-
Let x=0,
6(0)+3(11)=3y
0+33=3y
33=3y
33/3=y
11=y
1. Solution is (0,11)

Again, let x =1
6(1)+3(11)=3y
6+33=3y
39=3y
39/3=y
13=y
2. Solution is (1,13).
Hope it helps!!!!

Answer 2

if x=-3 and y=5
then,
6*(-3)+3k=3*5
-18+3k=15
3k=15+16
3k=33
k=33/3
k=11
two soloution are,
6x-3y=-33
if x=0
then
y=11
so first point is (0,11)
if x=1
then
y=(0,9)
Hope it helps!