find the value of k if 3 is root of 3x²+(k)x+9=0,then k=?
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Answered by
1
if 3 is one of the root then ,
x = 3
3(9) + 3k + 9 = 0
27 + 3k + 9 = 0
3k + 36 = 0
3k = -36
k = -12
Answered by
1
Answer:
-12
Step-by-step explanation:
As 3 is a root, so
3(3)^2 + k(3) + 9 = 0
=> 27 + 3k + 9 = 0
=> 3k = -36
=> k = -12.
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