Find the value of ‘ k ‘ if 3 % of k is 9
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Step-by-step explanation:
(k,3),(6,-2),(-3,4) are
collinear
here x
1
=k,y
1
=3
x
2
=6,y
2
=−2
x
3
=−3,y
3
=4
So, as given that the points are collinear, then,
x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)=0
k(−2−4)+6(4−3)+3(3+2)=0
k(−6)+6(1)+(−3)×5=0
−6k+6−15=0
−6k−9=0
k=
6
9
=
2
3
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