Find the value of k if 3kx(x-6)+3 here two equal roots? (hint b^2-4ac=0
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Step-by-step explanation:
3kx^2-18kx+3=0
here,b= -18k,a=3k,c=3
so,(-18k)^2-4.3k.3=0
324k^2=36k
k=36/324
k=1/9
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