Math, asked by vivek3589, 1 year ago

find the value of 'k' if (3x+2) is the factor of 4x^3+3x^2-4x+k​

Answers

Answered by poonam6540
3

Here is your answer hope it is helpful.

Attachments:
Answered by skh2
2

 \boxed{\sf{{p(x) = 4 {x}^{3} + 3 {x}^{2} - 4x + k}}}

Also,

 \boxed{3x + 2}

Is a factor of p(x)

 \rule{200}{3}

According to \sf{REMAINDER\:THEOREM} :-

If x-a is a factor of p(x)

Then

P(a) will be equal to Zero.

So,

3x + 2 = 0 \\  \\ 3x =  - 2 \\  \\ x =  \frac{ - 2}{3}

 \rule{200}{3}

As per Remainder theorem :-

 \boxed{ \boxed{p( \frac{ - 2}{3}) = 0}}

 \rule{200}{3}

 \boxed{4 {( \frac{ - 2}{3}) }^{3} + 3 {( \frac{ - 2}{3})}^{2} - 4( \frac{ - 2}{3}) + k = 0}\\  \\  \\ \boxed{4 \times  \frac{( - 8)}{27}  + 3 \times  \frac{(4)}{9}   +  \frac{8}{3} + k = 0}\\  \\  \\ \boxed{\frac{ - 32}{27} +  \frac{12}{9} +  \frac{8}{3} + k = 0} \\  \\  \\ \boxed{\frac{ - 32 + 36 + 72}{27} + k = 0}\\  \\  \\ \boxed{k +  \frac{76}{27} = 0}\\  \\ \\ \boxed{k =  \frac{ - 76}{27}}

 \rule{200}{4}

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