Find the value of k if 3x-y+5=0 and
6x-2y+k=0 has infinite solutions.
Answers
Answer:
6x-2y+k=0 k if 3x-y+5 =0and
So, your questions says that there are infinite ways to find the solution, it means we can solve it by any method, I would prefer addition method as it is easy and simple to solve °ω°, Lets start-
Our question will be like this- (3x-y+5=0)+(6x-2y+k=0) keep in mind that keeping two terms in bracket is very important, you had made the same mistake in your question]
Now time to add these bracket terms
=> (3x-y+=0)+(6x-2y+k=0)
=> 3x-y+=0+6x-2y+k=0 [Then we have to open brackets, as shown here]
=> 3x-y+=∅+6x-2y+k=∅ [Here you can see there are two zeros, that's why we will cut them as shown]
=> 3x-y+6x-2y+k [Left equation]
=> 3x+6x-y-2y+k [as you know that only same variables can be solved, i.e. 3x and +6x, -y and -2y, but k is alone so we can't do anything with it]
=> 9x-y-2y+k [3x + 6x = 9x]
=> 9x-3y+k
[Answer is 9x - 3y + k because they are alone variables and hence they can't be solved further]