find the value of K if(4,1) is a solution of 3x+2y=k
Answers
Answered by
14
Let the equation be given as:---
=) 3x-ky=8. ----------------(1)
It is given that point P(1,-1) is the solution so it satisfy the given equation.
Put x=1 & y= -1 in the given equation. ----- (1 ) we get
=) 3(1) -k(-1) =8
=) 3 + k = 8
=) K = 8-3 = 5 ans.
Now equation becomes :-
=) 3x -5y =8
Now another point lying on this line must satisfy the given equation
So put x=2 we get,
=) 3(2) -5y = 8
=) 6 - 5y =8
=) -5y = 2
=) y = -2/5
So point (2, -2/5) lies on the line : 3x-5y = 8
=) 3x-ky=8. ----------------(1)
It is given that point P(1,-1) is the solution so it satisfy the given equation.
Put x=1 & y= -1 in the given equation. ----- (1 ) we get
=) 3(1) -k(-1) =8
=) 3 + k = 8
=) K = 8-3 = 5 ans.
Now equation becomes :-
=) 3x -5y =8
Now another point lying on this line must satisfy the given equation
So put x=2 we get,
=) 3(2) -5y = 8
=) 6 - 5y =8
=) -5y = 2
=) y = -2/5
So point (2, -2/5) lies on the line : 3x-5y = 8
nanu95star89:
please mark brilliant if you think
Answered by
46
here is ur answer:
k ( 4, 1 )
3x + 2y = k
3 × 4 + 2 × 1 = k
12 + 2 = k
k = 14
hope it helps you!
☺❤☺
k ( 4, 1 )
3x + 2y = k
3 × 4 + 2 × 1 = k
12 + 2 = k
k = 14
hope it helps you!
☺❤☺
Similar questions