Question

Find the value of *K*if -4 is zero of the polynomial,p(x)=x^2-x-(2k+2)


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Answer 1

Answer:

k=5

Step-by-step explanation:

-4 is the zero of x^2-x-(2k+2)

putting x =-4 we get

(-4)^2-4-(2k+2)=0[-4 is a zero hence x^2-x-(2k+2)=0]

we get

16-4-2k-2=0

12-2=2k

10=2k

k=5