Find the value of 'k' if 4x^2+kx+k-3=0has equal roots.
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Hi there!
For Equal roots :
Discriminant = 0
=> b² - 4ac = 0
=> k² - 4(4)(k-3) = 0
=> k² - 16k +48 = 0
=> k² - 12k - 4k +48 = 0
=> k(k-12) - 4(k-12) = 0
=> (k-4) (k-12) = 0
=> k = 4 Or 12
[ Thank you! for asking the question. ]
Hope it helps!
For Equal roots :
Discriminant = 0
=> b² - 4ac = 0
=> k² - 4(4)(k-3) = 0
=> k² - 16k +48 = 0
=> k² - 12k - 4k +48 = 0
=> k(k-12) - 4(k-12) = 0
=> (k-4) (k-12) = 0
=> k = 4 Or 12
[ Thank you! for asking the question. ]
Hope it helps!
pnasreen20:
Thank u very muchhhh .... tomorrow i have mayhs exam...
Maths exam
welcome!
Which class ur studying
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