Question

Find the value of ‘k’ if 4x^3 − 2x^2 + kx + 5 leaves remainder -10 when divided
by 2x + 1.

Answer 1

Step-by-step explanation:

Apply remainder theorem with remainder = -10

$4 {x}^{3} - 2 {x}^{2} + kx + 5 = - 10$

$2x + 1 = 0 \\ x = - 1 \div 2$

Answer 2

Using X = -1/2 ( remainder theorem)

f(1/2) = K/2 + 4

∆ K / 2 + 4 = -10

∆ K = - 28

Hope this helps.