Find the value of ‘k’ if 4x 3 – 2x 2 + kx + 5 leaves remainder -10 when divided by 2x + 1.
please help
Answers
Answered by
1
Answer:
let,
f(x) = 4x^{3}-2 x^{2} + kx +5f(x)=4x3−2x2+kx+5
it is divided by 2x+1=0
⇒ value of x=-1/2
(u can find it out by:
2x+1=0 ∴ x=-1/2
)
remainder=-10
f(- \frac{1}{2} )=4( - \frac{1}{2}^{3} )-2( - \frac{1}{2})^{2} +k(- \frac{1}{2})+5=-10f(−21)=4(−213)−2(−21)2+k(−21)+5=−10
solving the above equation ans is : k=28
Answered by
33
Answer:
Answer:
Answer:
Step-by-step explanation:
We have the following theorem :
Remainder Theorem : When a polynomial p(x) is divided by a linear factor (x-a), then the remainder is p(a).
The given polynomial
Now,
Therefore, we must have
Thus, the required value of k is 28
Similar questions