Question

find the value of k if 7y^2-3y-k=35 where y=-2...

Answer 1

7×14 - (3×-2) - k = 35
98 +6 - k = 35
k =104-35
therefore k = 69

Answer 2

Y=-2(given) So we will put the value of Y in P(X) P(X)=7y × 2 - 3y -k=35 P(X)=7×-2 × 2 -3 ×-2-k=35 P(X) =-28+ 6 - k=35 P(X)=34-k=35 P(X)=-k=35-34 P(X)=-k=1 P(X)=k=-1