Question

find the value of k, if 81y^2-k =(9y+1/2)(9y-1/2)

Answer 1

Step-by-step explanation:

81y²-k

= (9y)²- ( √k)²

( 9y+√k) ( 9y-√k)= (9y+1/2) ( 9y-1/2)..............given

comparing ,

√k= 1/2

thus k = 1/4

hope it helps you...