Question

Find the value of k. If area of triangle 4 square unit and vertices are P ( K,O) Q( 4,0) R(0,2)​

Answer 1

Answer:

sorry don't know the answer

Answer 2

Answer:

1/2 [K 0. 1]

[4. 0. 1]

[0. 2. 1] =±4

K=(0−2)−0(0)+1(8)=±8

−2K+8=±8

−2K=8−8

−2K=0

K=0

or −2K=−8−8

2K=16

K=8

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