Find the value of k if cos 35/sin55 + 2sin theta/cos[90-theta] =k/2
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Answered by
23
cos35/sin55 + 2 sintheta/cos(90-theta) = k/2
cos (90- 55)/sin 55 + 2 sin theta/ cos (90- theta) = k/2
sin 55/sin 55 + 2 sin theta / sin theta = k/2
[since cos ( 90- A)= sin A ]
1 + 2 = k/2
3 = k/2
k/2 = 3
k = 2×3
k= 6
cos (90- 55)/sin 55 + 2 sin theta/ cos (90- theta) = k/2
sin 55/sin 55 + 2 sin theta / sin theta = k/2
[since cos ( 90- A)= sin A ]
1 + 2 = k/2
3 = k/2
k/2 = 3
k = 2×3
k= 6
Answered by
9
Answer:
the value of k is 6
Step-by-step explanation:
cos(90-55)/sin 55 +2sin /sin =k/2
sin55/ sin55 +2=k/2
1 +2 =k/2
3=k/2
k=6
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