Question

find the value of k if equation has equal roots: kx^2-2root5x+4=0​

Answer 1

Answer:

1.25.

Step-by-step explanation:

Given equation is  $kx^{2} - 2 \sqrt{5}x +4=0$ .

For this, the roots are equal.

So, the discriminant, D = $b^{2}-4ac=0$

                                    => $(-2\sqrt{5} )^{2}-4(k)(4)=0$

                                    => 20 - 16k = 0

                                    => k = 5/4 = 1.25.