Find the value of k if extho is factor
Answers
Step-by-step explanation:
Consider the given polynomial.
Consider the given polynomial.x
Consider the given polynomial.x 4
Consider the given polynomial.x 4 −k
Consider the given polynomial.x 4 −k 2
Consider the given polynomial.x 4 −k 2 x
Consider the given polynomial.x 4 −k 2 x 2
Consider the given polynomial.x 4 −k 2 x 2 +3x−6k
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−k
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k)
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k)
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4 −3k−6k=0
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4 −3k−6k=0−9k=0
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4 −3k−6k=0−9k=0k=0
Consider the given polynomial.x 4 −k 2 x 2 +3x−6kSince, x+k is the factor of given polynomial So, put x=−kTherefore,(−k) 4 −k 2 (−k) 2 +3(−k)−6k=0k 4 −k 4 −3k−6k=0−9k=0k=0Hence, the value of k is 0.
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