Question

find the value of k if following equation have equal roots :k+4 =(x²+k+1)x+1=0​

Answer 1

Answer:

-3

Step-by-step explanation:

Discriminant,

D=b

2

−4ac

D=(k+1)

2

−4(k+4)

D=k

2

−2k−15

D=(k−5)(k+3)

If the roots of the given equation are real and equal, then,

D=0

(k−5)(k+3)=0

k=5,−3