Question

Find the value of k, if (k-1) is a factor of p(x). where p (x)=2x² + kx + √2.​

Answer 1

${\sf{\underline{Question:-}}}$

Find the value of k, if $(k-1)$ is a factor of $p(x)$ where $p (x)=2x² + kx + \sqrt{2}.$

${\sf{\underline{Solution:-}}}$

If $x - 1$ is a factor of given $eq^{n}$, then it will satisfy this $eq^{n}$ ,$x - 1 = 0, x = 1kx,$

$\implies{2x^{2} + kx + \sqrt{2}}$

$\implies{2x^{2} + k + \sqrt{2}} = 0$

$\implies{k = -(\sqrt{2} + 2)}$

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