Question

Find the value of k, if (k,2) is the solution of the equation 2x +3y +6 = 0
and options are= -12,6,-6,12​

Answer 1

Answer:

(X,Y,Z)=(5,−2,−1)×(2,−1,0)=(−(−1)(−1),(−1)(2),5(−1)−(−2)(2))=(−1,−2,−1)  

(x,y)=(X/Z,Y/Z)=(−1−1,−2−1)

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

(X,Y,Z)=(5,−2,−1)×(2,−1,0)=(−(−1)(−1),(−1)(2),5(−1)−(−2)(2))=(−1,−2,−1)

(x,y)=(X/Z,Y/Z)=(−1−1,−2−1)