Find the value of k, if kx + 3y - 1 = 0, 2x + y + 5 = 0 are conjugate lines with respect to circle x^2 + y^2 - 2x - 4y - 4 = 0.
Ans : 2
Answers
Answered by
40
Step-by-step explanation :-
Given that :
- Equation of circle is .
- Equation of line are .
Here :
So :
∵ If the lines are conjugate w..r. to the circle then .
Answered by
0
Concept:
The set of all points in the plane that are a fixed distance (the radius) from a fixed point is called a circle (the centre). A radius is the distance between any two points on a circle and the centre. The polar of P and Q are called conjugate lines with respect to the circle S = 0 if P and Q are conjugate points with respect to the circle S = 0.
Given:
Equation of circle:
Conjugate lines
Find:
The value of k in conjugate lines.
Solution:
The radius of the circle:
Condition for conjugate lines:
Hence, the value of is .
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