Math, asked by Varad0019, 10 months ago

find the value of k, if Kx +3y = K-3 and 12x + KY =K represent coincident line.

Answers

Answered by abhi178
40

Therefore the value of k = 6.

Given : two equations ; kx + 3y = k - 3 and 12x + ky = k represent coincident lines.

To find : The value of k.

solution : we know, two lines a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 represent coincident lines.

only if a₂/a₁ = b₂/b₁ = c₂/c₁

⇒12/k = k/3 = k/(k - 3)

12/k = k/3

⇒12 × 3 = k²

⇒k² = 36 = 6²

⇒k = 6 , -6 ..........(1)

again, k/3 = k/(k - 3)

⇒k(k - 3) = 3k

⇒k² - 3k = 3k

⇒k² - 6k = 0

⇒k(k - 6) = 0

⇒k = 0, 6 ...........(2)

taking common values of k from equations (1) and (2) we get,

k = 6

Therefore the value of k = 6

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Answered by Rockboy742
2

Answer:

k=6

Step-by-step explanation:

Answer proved above :)

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