Question

Find the value of 'k' if kx (x-2) + 6 = 0 has equal roots.​

Answer 1

Answer:

6

Step-by-step explanation:

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Answer 2

Answer:

equal roots means

D=$b^{2}$-4ac=0

kx(x-2)+6=0

$kx^{2}$-2kx+6=0

a=k,b=-2k,c=6

$(-2k^{2} )$-4*k*6=0

$4k^{2}$-24k=0

4k(k-6)=0

k=1/4 or k=6

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