Question

find the value of k if kx(x-2)+6=0 has repeated roots​

Answer 1

Heya!!!

Answer to your question:

kx^2-2kx+6=0

For equal roots ,

d=0

b^2 -4ac=0

4k^2 -24k=0

4k (k-6)=0

k=0,6

Hope it helps ^_^