Question

find the value of k, if kx(x-2)+6=0 has two equal roots.

Answer 1

Answer:

Find it in the attachment

Answer 2

Answer:

Step-by-step explanation:

D=(b)^2-4ac

Here a=k,

B=-2k

C=6

D=(b)^2=4ac

(-2k)^2=4(k) (6)

(4k^2)=24k

4k^2-24k=0

4k(k-6)=0

K=6