Question

find the value of k if kx²+2x+1=0 had real roots​

Answer 1

Answer:

since, given quadratic equation has real roots

so, D=0

b²-4ac=0

2²-4×k×1=0

4-4k=0

4k=4

k=1

Answer 2

Answer:

k less than or equal to 1

Step-by-step explanation:

according to b²-4ac rule, (2)²-(4k) >or=0

4-4k>=0

4>=4k

1>=k

k<=1

k is less than or equal to 1