Question

find the value of k , if kx2+4x+1​

Answer 1

Answer:

The answer to the given question is k<4, the equation have real and distinct roots.

Step-by-step explanation:

Given quadratic equation:

kx² + 4x + 1 = 0

Compare the above question with

ax²+ bx+c = 0 , we get

Discriminant(D) >0

b²- 4ac> 0

⇒ 4² - 4×k×k> 0

⇒ 16- 4k>0

⇒ -4k > -16

Divide both sides with (-4)

⇒ k < 4

Therefore,

For all real value of k<4, the equation have real and distinct roots.

Hope it helps you......

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