Question

Find the value of K if Kx2 - 8√2 x + 4= 0 has equal real roots.
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Answer 1

$\bold{ \colorbox{lightgreen}{verified \: answer}}$

Answer:

$k = 8$

Step-by-step explanation:

If they have real roots, then discriminant D will also be equal to zero.

$\bold{ {b}^{2} - 4ac = 0}$

$\bold{ {(8 \sqrt{2}) }^{2} - 4 \times k \times 4 = 0}$

$\bold{128 - 16k = 0}$

$\bold{ - 16k = - 128}$

$\bold{k = \frac{ - 128}{ - 16} }$

$\bold{ \boxed{ \bold{k = 8}}}$

Hence the value of K is 8

Answer 2

Answer:

8

Step-by-step explanation:

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