Question

find the value of k if LCM (k,9) =18 & HCF ( k,9) = 3​

Answer 1

Step-by-step explanation:

if LCM is 18

18=k×9

K=18/9

k=2

for HCF I don't know

Answer 2

$\begin{gathered}\begin{gathered}\bf \: Given \:  - \begin{cases} &\sf{first \: number = 9} \\ &\sf{LCM (k,9) = 18}\\ &\sf{second \: number = k}\\ &\sf{HCF ( k,9) = 3} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \: To\:find - \begin{cases} &\sf{value \: of \: k}  \end{cases}\end{gathered}\end{gathered}$

$\large\underline\purple{\bold{Solution :- }}$

Given that

• First number = 9

• Second number = k

• HCF ( k,9) = 3

• LCM (k,9) = 18

We know that

• LCM × HCF = Product of two numbers

$\rm :\implies\:9 \times k = 3 \times 18$

$\rm :\implies\:k = \dfrac{18 \times 3}{9}$

$\rm :\implies \: \boxed{ \green{ \bf \:k \: = \: 6 }}$