Question

Find the value of k, if linear pair kx- y =2, 6x - 2y =3 have unique solution​

Answer 1

The given equations can be written as

kx - y - 2 = 0

6k - 2y - 3 = 0

These equations have a unique solution only if

$\frac{k}{6} \: unequal \: to \: \frac{ - 1}{ - 2}$

i.e. k unequal to 3

Thus, for any k unequal to 3, The given pair of linear equations will have a unique solution.

Answer 2

Answer:

Therefore, for all real values of k except k≠3

Above equation has unique solution.

Step-by-step explanation:

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