find the value of k if of the polynomial x square - (K+ 6 )X +( 2 k - 1 )has sum of its zeros half of their product
Answers
Answered by
6
K=7
EQUATION WAS WRONG EQUATION IS:-
X^2-(K+6)X+2(2K-1)=0
SOLUTION:-
◆ Given,
2(α+β)=αβ
◆ α+β = -b/a = - ( - { k+6 } )/1
◆ αβ = c/a = 2(2K-1)/1
● 2(α+β) = αβ
● 2(K+6) = 4K -2
● 2K + 12 + 2 = 4K
● 2K = 14
● K = 7
Answered by
1
Answer:
Answer:Answer is 7...................
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