Question

find the value of k if one equations has equal and real roots .(k+1)x^2-2(k+4)x+2k​

Answer 1

it has real and equal roots

that means alpha = 0, beta = 0

where as alpha and beta are the roots of quadratic equation.

(k+1)x^2-2(k+4)x+2k

•°• substituting x = 0

(k+1)0^2-2(k+4)0+2k = 0

0 - 0 + 2k = 0

k = 0/2 = 0

value for k is 0